AFC 1. Kansas City (2-0) AFC West leaders 2. Indianapolis (2-0) AFC South leaders 3. Cincinnati (2-0) AFC North leaders 4. N.Y. Jets (1-1) AFC East leaders 5. Pittsburgh (2-0) Wild card 6. Buffalo (1-1) Wild card 7. New England (1-1) 8. Miami (1-1) 9. Tennessee (1-1) 10. Denver (1-1) 11. Jacksonville (1-1) 12. Cleveland (1-1) 13. San Diego (0-2) 14. Oakland (0-2) 15. Baltimore (0-2) 16. Houston (0-2)
NFC 1. Washington (2-0) NFC East leaders 2. Tampa Bay (2-0) NFC South leaders 3. Chicago (1-1) NFC North leaders 4. San Francisco (1-1) NFC West leaders 5. N.Y. Giants (2-0) Wild card 6. Seattle (1-1) Wild card 7. New Orleans (1-1) 8. Atlanta (1-1) 9. Philadelphia (1-1) 10. St. Louis (1-1) 11. Detroit (1-1) 12. Carolina (1-1) 13. Dallas (1-1) 14. Minnesota (0-2) 15. Green Bay (0-2) 16. Arizona (0-2)
Wild Card Matchups: AFC: Buffalo at Cincinnati, Pittsburgh at N.Y. Jets NFC: Seattle at Chicago, N.Y. Giants at San Francisco
First-round byes: AFC: Kansas City, Indianapolis NFC: Washington, Tampa Bay
(Note: For these seedings, I considered Seattle's (0-0) and St. Louis' (1-1) divisional records equal.)
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New York leads the AFC East because they have the best division record (or technically, they have the best won-lost-tied percentage in games among the tied clubs [1-0, while Miami is 0-1, and NE and Buffalo are 0-0]).
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Originally posted by Mr. BoffoNew York leads the AFC East because they have the best division record (or technically, they have the best won-lost-tied percentage in games among the tied clubs [1-0, while Miami is 0-1, and NE and Buffalo are 0-0]).
Also, Buffalo beats New England based on strength of schedule. Buffalo's played Houston and Tampa Bay (combined 2-2) and New England's played Carolina and Oakland (combined 1-3).
I know Oakland vs. Dallas would have been big in the 70's, but if it is between the Raiders on Thanksgiving and the Chargers vs. Cowboys on Thanksgiving, I'd go with the latter at this point in the 21st century.