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The 7 - Movies & TV - The Price is Right double showcase winner rule?
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StingArmy
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#1 Posted on 15.5.06 1159.57
Reposted on: 15.5.13 1200.15
On today's episode of The Price is Right, a woman won both showcases with a bid of $15,000. The retail price of her showcase was $15,247.

I feel like I remember about 10+ years ago, the double showcase winner rule was "be within $1,000 of your showcase without going over." More recently, I thought the rule had changed to "be within $100 of your showcase without going over." However, if that's the case, then they must have change the rule again for this woman to win both showcases.

Anybody know the current rule and/or its history?

- StingArmy
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CRZ
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#2 Posted on 15.5.06 1220.07
Reposted on: 15.5.13 1220.19
    Originally posted by StingArmy
    Anybody know the current rule and/or its history?

http://en.wikipedia.org/wiki/The_Price_Is_Right#The_Showcase
rinberg
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#3 Posted on 15.5.06 1228.33
Reposted on: 15.5.13 1228.45
To elaborate on Fearless Leader's post:
    Originally posted by wikipedia.org
    The contestant nearest to the price of his own showcase without going over wins his showcase. If both contestants go over, neither player wins his showcase. Beginning in the spring of 1974, if the winner is less than $100 away from (Seasons 2-26) or within $250 of (Season 27 onward) the price of his own showcase, he wins both showcases. If the two contestants are exactly the same distance from the actual prices (in other words, if there is a tie) without going over, each wins his own showcase; this has happened exactly once in the show's history. If there is a tie where the differences are within the Double Showcase range, both contestants win both showcases; this has never happened.


(I had already looked it up and was about to post when I saw HIS post....)
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